In the context of linear algebra and symplectic geometry, the Williamson theorem concerns the diagonalization of positive definite matrices through symplectic matrices.[1][2][3]
More precisely, given a strictly positive-definite 2n\times 2n Hermitian real matrix M\in\mathbb{R}^{2n\times 2n}, the theorem ensures the existence of a real symplectic matrix S\in\mathbf{Sp}(2n,\mathbb{R}), and a diagonal positive real matrix D\in\mathbb{R}^{n\times n}, such that
SMS^T = I_2\otimes D \equiv D\oplus D,
where I_2 denotes the 2x2 identity matrix.
Proof
The derivation of the result hinges on a few basic observations:
- The real matrix
M^{-1/2} (J\otimes I_n) M^{-1/2}, withJ\equiv\begin{pmatrix}0&1\\-1&0\end{pmatrix}, is well-defined and skew-symmetric. - For any invertible skew-symmetric real matrix
A\in\mathbb{R}^{2n\times 2n}, there isO\in\mathbf{O}(2n)such thatOAO^T= J\otimes \Lambda, where\Lambdaa real positive-definite diagonal matrix containing the singular values ofA. - For any orthogonal
O\in\mathbf O(2n), the matrixS= \left(I_2\otimes\sqrt D\right)O M^{-1/2}is such thatSMS^T=I_2\otimes D. - If
O\in\mathbf O(2n)diagonalizesM^{-1/2} (J\otimes I_n) M^{-1/2}, meaning it satisfies
OM^{-1/2} (J\otimes I_n) M^{-1/2}O^T=J\otimes\Lambda,
then S= \left(I_2\otimes\sqrt D\right)O M^{-1/2} is such that
S(J\otimes I_n)S^T=J\otimes (D\Lambda) .
Therefore, taking D=\Lambda^{-1}, the matrix S is also a symplectic matrix, satisfying S(J\otimes I_n)S^T=J\otimes I_n.
References
- ^ Williamson, John (1936). "On the Algebraic Problem Concerning the Normal Forms of Linear Dynamical Systems". American Journal of Mathematics. 58 (1): 141–163. doi:10.2307/2371062. ISSN 0002-9327. JSTOR 2371062
- ^ Nicacio, F. (2021-12-01). "Williamson theorem in classical, quantum, and statistical physics". American Journal of Physics. 89 (12): 1139–1151. arXiv:2106.11965. Bibcode:2021AmJPh..89.1139N. doi:10.1119/10.0005944. ISSN 0002-9505
- ^ Yusofsani, Mohammad (25 November 2018). "Symplectic Geometry and Wiliamson's Theorem". Retrieved 25 November 2018.