{{Short description|Electrical component or portion of a circuit that consumes electric power}} {{Refimprove|date=December 2009}} An '''electrical load''' is an electrical component or portion of a circuit that consumes (active) electric power,<ref name="Karady">{{cite book | last1 = Karady|first1 = George G.|last2 = Holbert|first2 = Keith E.| url = https://books.google.com/books?id=VzBMPDiCr84C&dq=%22load&pg=SA3-PA18 | doi = | id = | isbn = 978-1118498033 |title = Electrical Energy Conversion and Transport: An Interactive Computer-Based Approach|date = 2013-05-03| publisher=John Wiley & Sons }}</ref><ref name="Glisson">{{cite book | last = Glisson | first = Tildon H. | title = Introduction to Circuit Analysis and Design | publisher = Springer | year = 2011 | location = USA | pages = 114–116 | url = https://books.google.com/books?id=7nNjaH9B0_0C&dq=%22load&pg=PA83 | doi = | id = | isbn = 978-9048194421}}</ref> such as electrical appliances and lights inside the home. The term may also refer to the power consumed by a circuit. This is opposed to a power supply source, such as a battery or generator, which ''provides'' power.<ref name="Glisson" />
The term is used more broadly in electronics for a device connected to a signal source, whether or not it consumes power.<ref name="Glisson" /> If an electric circuit has an output port, a pair of terminals that produces an electrical signal, the circuit connected to this terminal (or its input impedance) is the ''load''. For example, if a CD player is connected to an amplifier, the CD player is the source, and the amplifier is the load,<ref name="Glisson" /> and to continue the concept, if loudspeakers are connected to that amplifier, then that amplifier becomes a new, second source (to the loudspeakers), and the loudspeakers will be the load for the amplifier (but not for the CD player, there are two separate sources and two separate loads, chained together in series).
Load affects the performance of circuits with respect to output voltages or currents, such as in sensors, voltage sources, and amplifiers. Mains power outlets provide an easy example: they supply power at constant voltage, with electrical appliances connected to the power circuit collectively making up the load. When a high-power appliance switches on, it dramatically reduces the load impedance.
The voltages will drop if the load impedance is not much higher than the power supply impedance. Therefore, switching on a heating appliance in a domestic environment may cause incandescent lights to dim noticeably.
==A more technical approach== When discussing the effect of load on a circuit, it is helpful to disregard the circuit's actual design and consider only the Thévenin equivalent. (The Norton equivalent could be used instead, with the same results.<ref>{{Cite web |title=Converting Between Thevenin and Norton Equivalent Circuits {{!}} DC Network Analysis {{!}} Electronics Textbook |url=https://www.allaboutcircuits.com/textbook/direct-current/chpt-10/thevenin-norton-equivalencies/ |access-date=2025-07-24 |website=www.allaboutcircuits.com |language=en}}</ref>) The Thévenin equivalent of a circuit looks like this:
[[image:Electric load0.png|center|thumb|322px|The circuit is represented by an ideal voltage source ''Vs'' in series with an internal resistance ''Rs''.]]
With no load (open-circuited terminals), all of <math>V_S</math> falls across the output; the output voltage is <math>V_S</math>. However, the circuit will behave differently if a load is added. Therefore, we would like to ignore the details of the load circuit, as we did for the power supply, and represent it as simply as possible. For example, if we use an input resistance to represent the load, the complete circuit looks like this:
center|322px|thumb|The input resistance of the load stands in series with ''Rs''.
Whereas the voltage source by itself was an open circuit, adding the load makes a closed circuit and allows charge to flow. This current places a voltage drop across <math>R_S</math>, so the voltage at the output terminal is no longer <math>V_S</math>. The output voltage can be determined by the voltage division rule:
:<math>V_{OUT} = V_S \cdot \frac{R_{L}}{R_{L} + R_S}</math>
If the source resistance is not negligibly small compared to the load impedance, the output voltage will fall.
This illustration uses simple resistances, but a similar discussion can be applied in alternating current circuits using resistive, capacitive, and inductive elements.
==See also== * Dummy load
==References== {{reflist}}
{{DEFAULTSORT:Electrical Load}} Category:Electrical circuits